1) if the radius increases the magnetic field lines go farther and farther so the strength of the magnet decrease. 2) if the number of turns increase then the magnetic field lines become denser. So the strength of the magnet increase.
How does the strength of magnetic field at the centre of a circular coil of a wire affected with radius of coil magnitude of current and direction of current?
The magnetic field strength varies directly with the number of turns of wire. It increases as the number of turns increases. Answer: The magnetic field at the centre of a circular coil of a wire is inversely proportional to the radius of the coil whereas Directly proportional to the number of turns of wire in the coil.
How does the magnetic field of a coil depend on the current in the coil?
A wire coil that is carrying a current produces a magnetic field B( r), where r is the distance from the center of the coil to the field point. The strength of the field B is proportional to the current I in the coil. The strength and direction of the field depend on r. ... For large distances both fields fall off as 1/r3.
How does the strength of the magnetic field at the centre of a circular coil of wire carrying current change when?
Answer: At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil . So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value.
How does the strength of the magnetic field depend on the current?
By pointing one’s right thumb along the direction of the current, the direction of the magnetic field can by found by curving one’s fingers around the wire. The strength of the magnetic field depends on the current I in the wire and r, the distance from the wire .
How do you calculate the magnetic field strength of a coil?
A current I through a long, straight wire produces a magnetic field with strength H=I/2πr at a distance r from the wire. So the field strength is inversely proportional to the distance from the wire.
How can we induce current in a coil?
- If a coil is moved rapidly between the two poles of a horseshoe magnet, then an electric current is induced in the coil.
- If a magnet is moved relative to a coil, an electric current is induced.
- By keeping it stationary and rotating a magnet inside it, the current in the coil can be induced.
What will be the magnetic field value at the center of a current carrying coil?
The pole of a magnet, a current-carrying wire or a moving charged particle in a magnetic field will feel a magnetic force. ... The magnitude of the force on a wire carrying current I with length L in a magnetic field is given by the equation. F=ILBsinθ where θ is the angle between the wire and the magnetic field.
How will be the magnetic field intensity at the center of circular current carrying coil change if the current through the coil is doubled and the radius of the coil is halved?
At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value .
What happens to the magnetic field at the center of circular coil when its radius is doubled keeping current constant?
At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil.So, if we doubled the radius the current will be halved .
How can you increase the strength of a magnetic field?
- increasing the number of turns on the coil.
- increasing the current.
- placing an iron core inside the solenoid.
How does the number of turns affect a coil magnetic field?
As the number of turns increases the number of paper clips held increase . This means that the strength of the magnet increases with increasing number of turns in the coil. ... If you double the number of turns, you double the strength of the electromagnet.
Which coil produces the strongest electromagnet?
The strongest continuous manmade magnetic field, 45 T, was produced by a hybrid device, consisting of a Bitter magnet inside a superconducting magnet . The resistive magnet produces 33.5 T and the superconducting coil produces the remaining 11.5 T.
How do you calculate the force of a coil?
The force is F=A *B^2/2*mu_knot . For a traditional solenoid, a common expression for magnetic field is: B=Bsol=mu_knot*N*I/g, where g = gap. Then, F=mu_knot*A*(NI/g)^2/2 [same as your equation, without NdFeB.]
How is electromagnetic strength calculated?
To find the strength in gauss you must multiply the number of turns of wire in the electromagnet by the amperage .So for a example if you have a electromagnet with 20 turns of wire with 10 amps going through the wire then you multiply 20 by 10 and that will equals 200 so the magnetic feild it’s producing is 200 gauss.
How do you calculate the electromagnetic field strength?
The strength of an electric field E at any point may be defined as the electric, or Coulomb, force F exerted per unit positive electric charge q at that point, or simply E = F/q .
