How Many And Gates Are Required For A 1 To 8 Multiplexer Difficult Level Easy?

by | Last updated on January 24, 2024

, , , ,

How many AND gates are required for a 1-to-8 multiplexer? Explanation: The number of AND gates required will be equal to the number of outputs in a demultiplexer, which are 8 .

How many gates are required for a 1 to 8 multiplexer?

For a 1 to 8 multiplexer a total of 8 AND gates are required.

HOW MANY AND gate and OR gate is required for constructing 8 1 multiplexer?

How many AND gates are required for a 1-to-8 multiplexer? Explanation: The number of AND gates required will be equal to the number of outputs in a demultiplexer, which are 8 .

How many gates are required for a 1 to 16 multiplexer?

We know that 8×1 Multiplexer has 8 data inputs, 3 selection lines and one output. Whereas, 16×1 Multiplexer has 16 data inputs, 4 selection lines and one output. So, we require two 8×1 Multiplexers in first stage in order to get the 16 data inputs.

How many selected lines would be required for an 8 line to 1 line multiplexer?

How many select lines would be required for an 8-line-to-1-line multiplexer? Explanation: 2 n input lines, n control lines and 1 output line available for MUX. Here, 8 input lines mean 2 3 inputs. So, 3 control lines are possible.

How many and gates are required for a 1 to 4 demultiplexer?

From the above Boolean expressions, a 1-to-4 demultiplexer can be implemented by using four 3-input AND gates and two NOT gates as shown in figure below. The two select lines enable a particular AND gate at a time.

Is nor a universal gate?

The NAND and

How many 1 to 4 Line demux are required to construct a 1 to 64 line Demux?

of select lines. Therefore, for 1:4 demultiplexer, 2 select lines are required. Explanation: A demultiplexer sends a single input to multiple outputs, depending on the select lines.

How many select lines will a 1 to 16 de multiplexer will have?

We know that 8×1 Multiplexer has 8 data inputs, 3 selection lines and one output. Whereas, 16×1 Multiplexer has 16 data inputs, 4 selection lines and one output.

How does JK flip flop work?

The J-K flip-flop is the most versatile of the basic flip-flops. It has the input- following character of the clocked D flip-flop but has two inputs,traditionally labeled J and K. If J and K are different then the output Q takes the value of J at the next clock edge.

How many inputs are needed for a 1/16 decoder?

The HEF4515B is a 1-of-16 decoder/demultiplexer, having four binary weighted address inputs (A0 to A3), a latch enable input (EL), and an active LOW enable input (E). The 16 outputs (O0 to O15) are mutually exclusive active LOW.

Can an encoder be called a multiplexer?

10. Can an encoder be called a multiplexer? Explanation: A multiplexer or MUX is a combination circuit that contains more than one input line, one output line and more than one selection line. Whereas, an encoder is also considered a type of multiplexer but without a single output line and without any selection lines.

What is the purpose of multiplexer?

A multiplexer makes it possible for several input signals to share one device or resource , for example, one analog-to-digital converter or one communications transmission medium, instead of having one device per input signal. Multiplexers can also be used to implement Boolean functions of multiple variables.

Why are NAND and NOR gates more popular?

NAND and NOR gates are more popular as these are less expensive and easier to design . Also other functions NOT AND OR can easily be implemented using NAND/NOR gates. Thus NAND NOR gates are also referred to as Universal Gates.

How many NAND gates are used to form an AND gate?

AND: You can create an AND gate by using two NAND gates . The first NAND gate does what NAND gates do: returns LOW if both inputs are HIGH and returns HIGH if both inputs are anything else. Then the second NAND gate is configured as a NOT gate to invert the output from the first NAND gate.

What is full adder with truth table?

Full Adder is the adder which adds three inputs and produces two outputs . The first two inputs are A and B and the third input is an input carry as C-IN. The output carry is designated as C-OUT and the normal output is designated as S which is SUM.

Charlene Dyck
Author
Charlene Dyck
Charlene is a software developer and technology expert with a degree in computer science. She has worked for major tech companies and has a keen understanding of how computers and electronics work. Sarah is also an advocate for digital privacy and security.