(a) The highest resistance is when the resistances are connected in series. Hence, the highest resistance is 48 Ω. Hence, the lowest resistance is 2 Ω .
What is the a highest B lowest total resistance that can be secured by combinations of four coils of resistances 4 ohm 8 ohm 12 ohm and 24 ohm?
What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω? R = 4 + 8 + 12 + 24 = 48 Ω .
What is a the highest B the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω 8 Ω 12 Ω 32 Ω?
There are four coils of resistances 4 Ω, 8 Ω, 12 Ω and 24 Ω, respectively. hence, R=2 ohms is the least value of resistance that we can get from all of the above 4 resistors combinations.
What is the highest and lowest resistance which can be produced by connecting four resistors having the following resistances 4 ohm 8 ohm 12 ohm 24 ohm?
(a) To get the highest resistance, all the resistors must be connected in series. Therefore, the highest resistance is 48 Ω. (b) To get the lowest resistance, all the resistors must be connected in parallel. Therefore, the lowest resistance of the arrangement is 2 Ω .
What is the lowest resistance that can be obtained?
Hence, the lowest resistance is 2 ohms .
What is a the highest resistance?
Answer Expert Verified
(a) The highest resistance is when the resistances are connected in series. Total resistance in series = R1 + R2 + R3 + R4 Total resistance in series = 4 + 8 + 12 + 24. Total resistance in series = 48 Ω Hence, the highest resistance is 48 Ω.
How can three resistors of Resistance 2 ohm 3 ohm and 6 ohm?
There are three resistors of resistances 2 Ohm, 3 Ohm, and 6 Ohm respectively. ... Hence, the total resistance of the circuit is 4 Ω. (b) To obtain a total resistance of 1Ω from three resistors of 2Ω, 3Ω and 6Q, all the three resistors should be connected in parallel.
What is a the highest B the lowest total resistance that can be secured by combination of four coils?
Ans: Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω. ∴ 2 Ω is the lowest total resistance.
What is the lowest resistance that can be obtained by combining 10 resistors having resistance 1 ohm?
1/10 Ω
What is the resistance between A and B?
The three resistance of 20 ohm, 10 ohm and 20 ohm on the extreme right side are in series. So, the resultant of these three resistances = 20 + 20 + 10 = 50 ohms. Now, the resistances 10 ohms, 18.75 ohms and 10 ohms are in series. Therefore, resultant resistance = 18.75 + 10 + 10 = 38.75 ohms.
What will be the equivalent resistance between A and B?
So we get the equivalent by the formula, 1Req=1R1+1R2+1R3+.... Now in the top wire in between the points A and B we have 2 resistances which are in series. So the equivalent resistance between the points A and B will be 11R15 .
What is resistance between A and B in the given network?
The resistance of the combination is, R=1+1=2Ω
What type of wire has the lowest resistance?
A silver wire has a lower resistance than a lead wire*. Resistivity is a characteristic of a substance (like density) and can be found in tables like the one below.
How do you find effective resistance?
The effective resistance between vertices a and b (after connecting a voltage source between them) is defined as the potential difference between a and b per unit net current from a to b. In other words, Rab = va vb Iab . Once we fix the current from a to b to be Iab = 1, the effective resistance becomes Rab = va vb.
How do you find the lowest resistance?
Take the nominal value and multiply it by 1 + your tolerance, which is (1+0.1). Then take the nominal value and multiply it by 1 – tolerance, or (1-0.1). The highest possible value is 517 K. The lowest possible value is 423 K .
How many resistors do I need for 88 Ohm?
Therefore, 4 resistors of 88Ω ( in parallel) are required to carry 10 A on a 220 V line.
