What Is The Radius Of 2nd Shell Of Hydrogen Atom? - Fixanswer

If potential energy between a proton and an electron is given by ∣

U∣=ke2/2R3

, where e is the charge of electron and R is the radius of atom, then radius of Bohr’s orbit is given by (h = Planck’s constant, k = constant)

What is the radius of first shell of hydrogen atom?

The radius of first Bohr orbit of hydrogen atom is

0.529 A ̊

.

What is the radius of third shell of hydrogen atom?

the formulae of any radius of an orbit is = 0.529×n^2/z . so the radius of the third orbit of hydrogen is = 0.529×3^2/1=

4.761 Å

. ……

What is the radius of second orbit of He+?

The correct option is (a)

1.058 Å

.

What is the radius of second Bohr orbit of hydrogen atom in NM?

0. 529 A ̊

What is the circumference of the second orbit of hydrogen atom?

The circumference of the second orbit of electron in hydrogen atom os 400nm, the de-Broglie wavelength of electron corresponding to the circumference of same orbit is

200 nm

.

How do you find the radius of a hydrogen atom?

The allowed electron orbits in hydrogen have the radii shown. These radii were first calculated by Bohr and are given by the equation

rn=n2ZaB r n = n 2 Z a B

. The lowest orbit has the experimentally verified diameter of a hydrogen atom.

What is the atomic radii of hydrogen and hydrogen like atoms?

For any two covalently bonded atoms it is calculated by dividing the distance between the nuclei of the atom by two. We know that hydrogen atom has an atomic number as 1 and its atomic weight is 1.008u. The atomic radius of the hydrogen atom is measured as

53pm

. Hence, option C is correct.

What is the radius of 5th orbit of hydrogen atom?

– Therefore the energy associated with the 5th orbit of the hydrogen atom is $-8.68times {{10}^{-20}}$ J/atom . – Therefore the radius of the 5th Bhor’s orbit of the hydrogen atom is

1.3225 nm

or 13.225$overset{o}{mathop{text{A}}},$.

What would be the radius of second orbit if radius of first orbit of hydrogen is 0.53 A?

Answer: 1.06 A° is the radius of the second orbit of helium ion.

What is the radius of hydrogen atom in Angstrom?

The radius of hydrogen atom in ground state is

0.53 angstrom

.

What is the radius of nth orbit of hydrogen atom?

Logic and Solution: Atomic number, Z is equal to 1. Hence the radius of n
^th
orbit,

r
_n
= 0.529n
²
Å

.

How many times is the radius of the 3rd shell of the hydrogen atom as compared to that of the radius of the first shell?

nine

to the radius of first orbit.

How do you find the radius of an atom in Class 11?

The

distance from the centre of the nucleus to the outermost shell

containing electrons. The distance from the centre of the nucleus to the point up to which the density of the electron cloud is maximum.

In which Shell of be 3ion the radius is equal to the radius of ground state of H atom?

Thus

2
^nd
state of the triply ionised beryllium(Be
^{3 +}
ion)

has the same orbit radius as that of ground state of hydrogen atom.

What is the order of the radius of an electron orbit in hydrogen atom?

r=r0(0.53)A∘

.

What is the shell radius?

The radius of each cylindrical shell is

the horizontal distance from the current x value to the axis of rotation

. So if we rotate about the line x=2, the distance between our current x position and the axis of rotation is 2-x. Likewise, if we rotate about the y axis (aka x=0) the radius is x-0=x.

What is the radius of a cylindrical shell?

Say the outer cylindrical shell has radius r2 and the inner has radius r1. Let ∆r = r2 − r1, the thickness of the cylindrical shell, and let r = (r2 + r1)/2, the average of the outer and inner radii of the cylindrical shell. The volume of the cylindrical shell is then

V = 2πrh∆r

.

What is the ratio of radius of 2nd and 3rd orbit of H atom?

1:2:3

.

Which orbit of beryllium ion is same as hydrogen atom 2nd orbit radius?

2nd state of the triply ionised

beryllium(Be3+ ion)

has the same orbit radius as that of ground state of hydrogen atom.

When an electron in hydrogen atom jumps from third orbit to the 2nd orbit?

If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits

a photon of wavelength lambda

. When it jumps form the 4th orbit to the 3dr orbit, the corresponding wavelength of the photon will be. Transition :3→2⇒ Wavelength λ.

What is second Bohr orbit of hydrogen atom?

The energy of second Bohr orbit of the hydrogen atom is

−328kJ mol−1

. Hence, the energy of fourth Bohr orbit would be: Chemistry. The energy of the second Bohr orbit in the hydrogen atom is −3.41 eV.

What is the radius of the first Bohr orbit in He+?

The radius of the first Bohr orbit of hydrogen atom is

0.52

.

What is radius of 4th Bohr orbit?

The radius of the fourth orbit of hydrogen is

0.85 nm

.

How much is the radius of an atom?

Nucleus and shells

the radius of an atom is

about 0.1 nm

(1 × 10
^{– 10}
m)

What is the value of radius of 1st orbit?

The radius of the first bohr orbit (n=1) of hydrogen atom is

53.4 pm

.

What is the covalent radius of hydrogen?

The covalent radius of hydrogen is

0.37A^∘

.

What is the circumference of the orbit?

Approximately 940 million kilometers

.

What is the circumference of an atom?

The circumference of the second orbit of an atom or ion having single electron ,is

4×10−9 m

.

How do you find the Bohr radius of a hydrogen atom?

The Bohr radius is a physical constant that is equal to the distance between the nucleus and the electron of a hydrogen atom in the ground state. Its value is given by the formula

0 = 4 0(h bar)2/ _e ( _e)2.

What is the radius in nm of the electron orbit of a hydrogen atom for n 1?

The orbital radius of an electron in energy level equals two of a hydrogen atom is

0.210 nanometers

.

What is the radius of hydrogen in ground state?

The radius of hydrogen in the ground state is

0.53 A^∘

.

What is the circumference of the fourth orbit in hydrogen atom?

The circumference of the 4th Bohr orbit in hydrogen atom is

5.32 nm

.

What is the longest wavelength of light in CM that can be used to cause this transition?

$ lambda = 3.6473{{ }} times {{ }}{10^{ – 7}}{{ M}} $ . i.e. $ {{lambda = 3647}}{{. 3 }}{{{A}}^{{o}}} $ . Therefore, the longest wavelength (in A) of light that can be used to cause this transition will be $

lambda = 3647.3

{{ }}{{{A}}^{{o}}} $ .