Answer: It is
2^14 memory
lacations can be addressed by a microprocessor with 14 address lines. Answer: 2 ^ 14 memory location can be addressed by 14 bit address line.
How many memory locations can be addressed by 20 address lines?
For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address
2
20
(1,048,576)
memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 2
32
(4,294,967,296) locations, or a 4 GiB address space.
How many memory location can be accessed if we are having an bit address bus?
If there are just 2 bits in the address, then there can only be 4 addresses, viz. So, if we have n bits to store an Address (n-bits in Address Register) or n-wires to transfer the address (Address bus of size 10), then we can have RAM
of 2
n
addresses
.
How many memory locations can be addressed using 10 bit address?
Notice that with ten address lines you can address the magic number of
1024 memory locations
, and this is the closest you can get to 1000 using this system – hence 1K = 1024.
How many bits are in a memory location?
One memory location stores 1 byte (
8 bits
). The basic storage unit for memory is 1 byte. If you need to store 4 bytes, and place the first byte at 0001, the last byte will be at 0004. That’s one byte at each of 0001, 0002, 0003, and 0004.
How much memory can be addressed with 15 address lines?
| Address bus size Addressable memory (bytes) | 12 4K | 13 8K | 14 16K | 15 32K |
|---|
How many different memory locations can be accessed using 12 bits?
Each memory location is one byte, while the address is 12-bit, with the capability to address up to
4096 locations
.
How many memory locations are addressed using 18 address bits how many address bits are needed to operate a 2 K 8 bit ROM memory?
8. How many memory locations are addressed using 18 address bits? Explanation: For n address bits, the memory location will consist of 2
n
bits. Using 18 address bits, 2
18
=
262,144
(= 256 K) words are addressed.
How many address locations can a 16-bit microprocessor with 8 bit data bus address?
There are 16 bits gling out to the memory so it can choose
64ki locations
. Then, each location contains 8 bits. The word size here may or may not match the CPU computation unit size, and this may or may not match the logical granularity in addressing.
How many memory locations can a 16-bit processor access?
A 16-bit integer can store
2
16
(or 65,536) distinct
values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.
What is memory addressing capacity for 32 address lines microprocessors?
32 Address lines means
2^32 possible addresses
, and a data bus 16 bits wide accommodates 2 bytes, so that means that in terms of bytes, the memory space is 2^33, or 8,589,934,592 bytes. This is otherwise known as 8GB.
What is the memory size if a computer has 16 bits for the memory address register and 8 bits for memory buffer register?
The answer is
64 KB
. You can address 2^16 words and each word is 8 bit (= 1 byte). Therefore it is 64 KB. If the word size was 16 bit.
How much memory can a 32 bit address?
Most computers made in the 1990s and early 2000s were 32-bit machines. The CPU register stores memory addresses, which is how the processor accesses data from RAM. One bit in the register can reference an individual byte in memory, so a 32-bit system can address a maximum of
4 GB (4,294,967,296 bytes) of RAM
.
How many memory addresses are there?
Each byte of main storage has an address. Most modern processors use 32-bit addresses, so there are
2
32
possible addresses
. Think of main storage as if it were an array: byte[0x00000000 …
How many bits are there in the physical address?
Physical addresses are
44 bits
and there are 4 protection bits per page.
How many types of addressing are there in memory?
In this challenge we will focus on
four different
memory address modes: Immediate Access. Direct Access. Indirect Access.
How many address and data lines will be there for a 16M 32 memory system?
How many address and data lines will be there for a 16M x 32 memory system? d. None of the above Correct solution is (c). Since there are 16M words, the number of address lines will be
24
, since 224 = 16M.
How many memory locations are identified by a processor with 8 bits address bus at a time?
The facile answer is “
256
” because 8 bits can only have 256 different values.
How many address lines are required if a microprocessor has to access 32k byte memory 13 14 15 16?
So basically
22 address lines
. With DRAM-DDR, some of these are CPU-internal (as RAM has a data bus of 64 bits currently, which is 8=2^3 bytes).
How many address lines are needed to address each memory locations in a 2048 * 4 memory chip?
ANSWER: 11
It means that a memory of 2048 words, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, so
11 address lines
.
What is the maximum memory addressing capacity of 8086?
Address Bus − 8085 has 16-bit address bus while 8086 has 20-bit address bus. Memory − 8085 can access up to 64Kb, whereas 8086 can access up to
1 Mb
of memory.
How many unique addresses would be required to access 2 to the 16 memory cells?
So 2 to the power of 16 is
65,536
, commonly referred to as 64K. The number of memory words addressed on a bus is 2 to the power of the width of the address bus, in this case 16. So 2 to the power of 16 is 65,536, commonly referred to as 64K.
What is the bit storage capacity of a ROM with a 1024×4 organization?
The answer is
2^20
that is one kilobytes.
How many 8 K 1 RAMs are required to achieve a memory with a word capacity of 8 K and a word length of eight bits?
| Q. How many 8 k × 1 RAMs are required to achieve a memory with a word capacity of 8 k and a word length of eight bits? | B. two | C. one | D. four | Answer» a. eight |
|---|
How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system?
7. How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system? Explanation: One 1024 * 1 RAM chips is of 1-bit. SO, for construction of 1024 * 8 RAM chip of 8-bits, it will require
8 chips
.
What is memory addressing capacity?
Techopedia Explains Memory Capacity
The memory capacity of a device is commonly expressed in
bytes, kilobytes, megabytes, gigabytes or terabytes
. … In the case of 32-bit CPUs, they can only address a memory capacity of up to 4 GB. As for a 64-bit computer, the memory capacity is unlimited.
How many bits of storage does a memory system contain if it has a 16k address space and is 8 bit addressable?
If each memory location holds one byte, the addressable memory space is 4 GB. Based on your input, 16k is the memory location with 8 bits(1byte) of data storage at each memory location. Hence the address bus length is
14 bits
.
What is the maximum supported memory size in a 16 bit architecture with 16 bit memory address if each memory address holds 1 byte data?
The microprocessor can access 216=65536 memory addresses, regardless of the size of data held at each memory address. If each memory address holds one byte (8 bits) of data then the total memory size that can be addressed directly is 216 bytes, which is 26 KiB=
64 KiB
.
What is the maximum memory capacity that an 8 bit address line can manage?
These processors have 8-bit CPUs with 8-bit data and 16-bit addressing. The memory on these CPUs is addressable at the byte level. This leads to a memory addressable limit of 2
16
× 1 byte =
65,536 bytes or 64 kilobytes
.
What is the maximum memory 8088 can access?
What is the maximum memory 8086 and 8088 can access? – Quora. The 8088 and 8086 used segmented addressing to allow these chips to address
1 MB
of memory using 20 address bits = 1,048,576).
What is the address space of a system with 16 bit addresses?
On a 16-bit system, the address bus was 24 bits wide, for a physical address space of
16 Mbytes
. On a 32-bit system, the address bus was also 32 bits wide, for a physical address space of 4 Gbytes.
Why can I only use 3gb of RAM?
Its because
you are using 32 bit version of windows
. Thats why its showing you that. 64 bit would show you all the ram installed.
What happens if I use 32-bit on 64 bit?
To put it in simple words, if you run a 32-bit program on a 64-bit machine, it
will work fine
, and you won’t encounter any problems. Backward compatibility is an important part when it comes to computer technology. Therefore, 64 bit systems can support and run 32-bit applications.
What is the RAM limit for 64 bit?
The theoretical memory limits in 16, 32 and 64 bit machines are as follows: 16 bit = 65,536 bytes (64 Kilobytes) 32 bit = 4,294,967,296 bytes (4 Gigabytes) 64 bit
= 18,446,744,073,709,551,616 (16 Exabytes)
How many different memory locations can be accessed using 12 bits?
Each memory location is one byte, while the address is 12-bit, with the capability to address up to
4096 locations
.
How many bits can 2k memory store?
How many bits can a 2k memory store? With regard to memory, 2k usually means 2*(2^10) — that is,
2048
. Now, depending on context, that may be 2048 bits, 2048 bytes ( 8*2048 bits), or 2048 words — (word-size-in-bits) * 2048 bits.
How many memory locations can a 16 bit processor access?
A 16-bit integer can store
2
16
(or 65,536) distinct
values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.
How many address locations can a 16 bit microprocessor with 8 bit data bus address?
There are 16 bits gling out to the memory so it can choose
64ki locations
. Then, each location contains 8 bits. The word size here may or may not match the CPU computation unit size, and this may or may not match the logical granularity in addressing.
What is 16K memory?
16K means
16,384 ‘storage locations’ of 8 bits
, thus 16KB. 64 x 16 means 64 storage locations of 16 bits, thus 128 (8 bit) bytes. The example you give for the Atmega is thus 16,384 times 16 (bits) is 32,768 (8 bit) bytes.
Are memory addresses in bits?
Memory addresses are numbers too, so on a 32-bit CPU the memory address consists of
32 bits
.
How many bits are stored in each location in memory RAM )?
One memory location stores 1 byte (
8 bits
). The basic storage unit for memory is 1 byte. If you need to store 4 bytes, and place the first byte at 0001, the last byte will be at 0004. That’s one byte at each of 0001, 0002, 0003, and 0004.
