8 books can be placed on a shelf in 8*7*6*5*4*3*2*1 ways. That equals to
40320
.
How many ways can 7 different books can be arranged on a shelf?
=
5040 ways
. Hence we can arrange 7 different books on a shelf in 5040 ways.
How many ways can 9 different books be arranged on a shelf?
We know that the two books that are kept together can be arranged in two ways. So, we will get the total number of ways we can arrange the $9$ books. Hence, we can arrange the $9$ on a shelf in $40320times 2=
80640$ ways
.
How many ways can books be arranged on a shelf?
There are
720 ways
.
How many combinations of 8 items are there?
Note: 8 items have a total of
40,320 different combinations
.
How many ways can 7 books be arranged on a shelf 5 at a time?
7 books can be arranged on a shelf 5 at a time in
2520 ways
.
How many ways can you arrange 9 different books on a shelf if there is space enough for only 5 books?
n how many ways can you place 9 different books on a shelf if there is space enough only 5 books? ution: Pn,r=frac n! m-r! Answer: There are
15120 ways
that 9 different books can bi P9,5=frac 919-5!
How many ways can 10 books be arranged on a shelf if one of the books is a Bible and it must be on one end?
question_answer Answers(1)
ways. ∴ hence the total number of arrangements =
9
!
How many ways can 11 books be arranged on a bookshelf?
So we found that the number of ways of arranging 11 books on a shelf is
39916800
.
How many ways 6 books out of 10 different books can be arranged in a book self so that 3 particular books are always together?
Hence the total number of ways of choosing 6 books from out of 10 books so that three particular books are always together is, by fundamental counting principle, 210x24x6 =
30240 ways
. I HOPE ITS HELPFUL TO YOU.
How many ways can you arrange 3 books on a shelf?
different bundles of novels, and we have to put this bundle and other 3 books onto the shelf. So the total number of ways is 3! × (3 + 1)! =
144
.
How many 8 letter combinations are there?
An eight-character password using only lowercase and uppercase characters has
200 billion possible combinations
.
How many ways are there to order 6 books on a shelf?
Therefore, we have
720 ways
of arranging 6 books on the shelf.
How many ways can something be arranged?
In more general terms, if we have n items total and want to pick k in a certain order, we get: n! / (n – k)! And this is the permutation formula: The number of ways k items can be ordered from n items:
P(n,k) = n! / (n – k)!
How many ways can you select 3 books from a collection of 7 books and then arrange them in shelf?
(a) Any arrangement is possible: 7 books can be arranged among themselves in 7! =
5040 ways
.
How many ways can 7 letters be arranged?
According to the probability, 7 letter word can be arranged in
5040 ways
, which is 7!.
How many ways can 5 books be arranged on a shelf if 2 of the books must remain together?
See it? Whoa, dude! That’s 5! So, there are
120 ways
to arrange five books on a bookshelf.
How many distinguishable permutations of letters are possible in the word ellipses?
18=
5040
There are 5,040 distinguishable permutations from the word ELLIPSES 4.
What is 5th number statement?
Step-by-step explanation: We are given to find the fifth number, where the first and second numbers are 1 and 2 respectively. We will consider the following two cases to find the fifth number which includes addition and multiplication. Thus, the 5th number can be
5 or 16
.
How many ways can the letters of the word psychology be arranged so that the two O’s do not appear together?
Total Possible arrangement =
10
!/2! . 2! Hence arrangements = 9! / 2!
How many ways can 8 books be arranged on a shelf such that a particular pair of books should always be together?
It can be in slots (1,2,3),(2,3,4),(3,4,5),… (6,7,8)=
6 ways
.
How many ways are there to arrange 10 books on a shelf?
now out of 10 books 1 is already filled, so we have 9 books and 5 places. ANS: Therefore the number of ways 10 books can be fit in 6 places is 10*9*8*7*6*5 =
1,51,200
.
How many ways can 10 items be arranged?
If the letters are all different, then they can be arranged in 10! = 10*9*8*7*6*5*4*3*2*1 =
3,628,800 ways
. If some of the letters are repeated, the number of arrangements will be 10! divided by the product of the factorials of the number of times each letter is repeated.
How many ways can 12 math textbooks be arranged on a shelf?
Solution: There are 3 choices for each of 12 books. The answer is
312
.
How many different ways can 11 books be arranged?
(or factorial 11) which is
39,916,800 ways
.
How many ways can 10 students can be arranged in a row?
Explanation: 10 students can be arranged in a row in
10
P
10
= 10! ways
.
How many ways can you arrange 8 books on a shelf if only 5 books can fit at a time?
8(7)(6)(5)(4)(3)(2)1 =
40,320 ways
to arrange 8 books on a shelf.
How many ways can you arrange 6 of 11 different books on a shelf?
6×5×6×7=
1260 ways
. Assuming order matters, there are 8 books in total.
How many ways can 6 numbers be arranged?
For any group of 6 numbers and letters, there are a possible
720 different permutations
or combinations that can be made.
How many ways 10 persons can be arranged such that 3 are never together?
Answer: 10 persons can be arranged such that 3 are always together in
241920 ways
.
How many combinations of three books can be chosen from a collection of 10 books?
You can pick 3 books out of 10 in
120 different ways
.
How many different ways can you choose 3 books from the 8 books on a shelf?
If you choose one for each type, you have 6 choices for the first type, 8 for the second and 10 for the third one. Therefore, the answer is 6×8×10=
480
.
How many ways can you arrange 4 books?
The total number of permutations is 6 X 4 = 24. There are
24 ways
to arrange the 4 items on a bookshelf.
What are the multiples of 8?
First, let’s list the first several multiples of eight:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88
. . .
What can you multiply to get 8?
8 × 6 = 48 8 multiplied by 6 to get 48 | 8 × 7 = 56 8 multiplied by 7 to get 56 | 8 × 8 = 64 8 multiplied by 8 to get 64 |
---|
How many ways can eight letters be arranged?
(eight factorial). ∴ There are
40,320 possible ways 8
students can be arranged in a line.
How many pairs can you make with 8?
So for 8 people there are 8! 4! 24=
105 possible sets of pairs
.
What does it mean to have 8 characters in a password?
Example Valid Reason | 42abcdef No Password contains only two character categories: digits and lowercase characters. |
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