The
8085 has no multiplication operation
. To get the result of multiplication, we should use the repetitive addition method. After multiplying two 8-bit numbers it may generate 1-byte or 2-byte numbers, so we are using two registers to hold the result.
Which instruction is used for multiplication of two 8-bit number?
| Address Mnemonics Operand | 200B | 200C | 200D INX H | 200E MOV M , A |
|---|
How can I add two numbers in 8085?
- Load the first number from memory location 2050 to accumulator.
- Move the content of accumulator to register H.
- Load the second number from memory location 2051 to accumaltor.
- Then add the content of register H and accumulator using “ADD” instruction and storing result at 3050.
Which instruction is used for BCD multiplication?
➢
AAM Instruction
– AAM converts the result of the multiplication of two valid unpacked BCD digits into a valid 2-digit unpacked BCD number and takes AX as an implicit operand.
What is size of result in case of 8-bit multiplication?
The maximum result from the multiplication of two 8-bit numbers can be
up-to 16-bits
.
How is multiplication used in 8051 microcontroller?
| Address Value | 20H FFH | 21H FFH | . . . | 30H 00H |
|---|
Which of the following instructions will multiply the content of the accumulator by 2?
The instruction ADD a
will add the content of the accumulator to itself; this is equivalent to multiplying by 2.
What is LHLD in microprocessor?
In 8085 Instruction set LHLD is a mnemonic that stands for
Load HL pair using Direct addressing from memory location whose 16-bit
address is denoted as a16. So the previous content of HL register pair will get updated with the new 16-bits value. … It occupies 3-Bytes in the memory.
What is accumulator in microprocessor?
The accumulator is
an 8-bit register that is a part of arithmetic/logic unit (ALU)
. This register is used to store 8-bit data and to perform arithmetic and logical operations. The result of an operation is stored in the accumulator. The accumulator is also identified as register A.
What is Subb in 8051?
The SUBB instruction
subtracts the specified byte variable and the carry flag from the accumulator
. The result is stored in the accumulator. This instruction sets the carry flag if a borrow is required for bit 7 of the result.
What is successive addition method?
In successive addition method,
one number is accepted and other number is taken as a counter
. The first number is added with itself, till the counter decrements to zero. Result is stored in DX register. Display the result, using display routine.
What is the largest possible result of multiplying two unsigned n-bit numbers?
The easiest way to think about this is to consider the maximum of the product, which is attained when we use the maximum of the two multiplicands. If value x is an n-bit number, it is at
most 2^n – 1
.
How do you calculate binary multiplication?
- 0 × 0 = 0.
- 0 × 1 = 0.
- 1 × 0 = 0.
- 1 × 1 = 1.
When we multiply an N-bit number to another N-bit number the size of the product is?
In general, an N × N multiplier multiplies two N-bit numbers and produces
a 2N-bit result
. The partial products in binary multiplication are either the multiplicand or all 0’s. Multiplication of 1-bit binary numbers is equivalent to the AND operation, so AND gates are used to form the partial products.
When multiplying two binary integers of lengths a and b how many bits are in the product?
1 Answer. When you multiply two numbers, the number of bits in the product cannot be less than max(m,n) and cannot be
more than (m+n)
. (Unless one of the two numbers is a 0).
Which register can be used for multiply and divide operation in 8051 microcontroller?
Now we will see another arithmetic operation. The divide operation to divide two 8-bit numbers using this 8051 microcontroller. The
register A and B
will be used in this operation.
Which register is used for the multiplication and division in 8051?
The B register
is only used for multiplication and division operations. The 8051 microcontroller consists of 4-input and output ports (P0, P1, P2, and P3) or 32-I/O pins.
What operation can be performed by using the instruction ADD A in 8085?
| Opcode Operand Meaning | ADD R M Add register or memory , to the accumulator | ADC R M Add register to the accumulator with carry | ADI 8-bit data Add the immediate to the accumulator | ACI 8-bit data Add the immediate to the accumulator with carry |
|---|
Which instruction is used for multiplying two unsigned bytes in register A and B?
The MUL instruction multiplies the unsigned 8-bit integer in the accumulator and the unsigned 8-bit integer in the B register producing a 16-bit product. The low-order byte of the product is returned in the accumulator.
What is LXI instruction?
We can use this
instruction to load data from memory location using the memory address
, which is stored in the register pair rp. … For an example, if the instruction is LXI H, FE50. It means that the FE50 is loaded into the HL register pair.
What will be the content of accumulator after execution of the following 8085 instructions?
The content of accumulator are
70 H
. Initially all flags are zero.
What is stack and stack pointer in 8085?
The stack is a LIFO (last in, first out) data structure implemented in the RAM area and is
used to store addresses and data when
the microprocessor branches to a subroutine. … They are the stack pointer, SP, and the program counter, PC. The Stack Pointer register will hold the address of the top location of the stack.
What is Adi in microprocessor?
Microprocessor8085. In 8085 Instruction set, ADI is a mnemonic, which stands for “
ADd Immediate to Accumulator
” and here “d8” stands for any 8-bit or 1-Byte of data. This instruction is used to add 8-bit immediate data to the Accumulator. The result of addition will be stored in the Accumulator.
What is word length in 8085 microprocessor?
The word length of 8085 is
8 bits
. For 8086 it is 16 bits.
How do I add two 32 bit numbers in assembly language?
- Step II : Load the LSB of first number into AX register.
- Step III : Load the MSB of first number into BX register.
- Step IV : Load the LSB of the second number into CX register.
- Step V : Load the MSB of the second number into DX register.
- Step VI : Add the LSBs of two number.
How do you add two 16 bit numbers in assembly language?
- Step I : Initialize the data segment.
- Step II : Get the first number in AX register.
- Step III : Get the second number in BX register.
- Step IV : Add the two numbers.
- Step V : Display the result.
What is the use of stack pointer in 8085 microprocessor?
Stack Pointer: It is used as
a memory pointer
. It points to a memory location in read/write memory, called the stack. It is always incremented/decremented by 2 during push and pop operation.
Why accumulators are used in microprocessor?
All microprocessors make use of an accumulator register
that can supply one number for an action, and where the result of an action will also be stored
. The size of the accumulator in terms of bits is used as a measure of the data unit capability of the microprocessor (as 8-bit, 16-bit, 32-bit, 64-bit, and so on).
What is RET in microcontroller?
Description: RET is
used to return from a subroutine previously called by LCALL or ACALL
. Program execution continues at the address that is calculated by popping the topmost 2 bytes off the stack. The most-significant-byte is popped off the stack first, followed by the least-significant-byte.
How can I add two 16 bit numbers in 8051?
THEORY. As there is only one 16-bit Register in 89C51, 16-bit addition is performed by using ADDC instruction twice, i.e. adding LSD first and MSD next.
DATAM1
– 12; DATAM2 = 56.
Why 8085 microprocessor is called accumulator based microprocessor?
| Before After | (4050H) CDH ABH |
|---|
What do the mnemonics DJNZ and Acall stand for?
JNZ – Jump if Accumulator Not Zero
.
JZ – Jump if Accumulator Zero
. LCALL – Long Call. LJMP – Long Jump.
What is DJNZ in microcontroller?
Home » Instructions » DJNZ. The DJNZ
instruction decrements the byte indicated by the first operand
and, if the resulting value is not zero, branches to the address specified in the second operand.
How do you multiply a binary number by 8?
to multiply by two, all digits shift one place to the left. to multiply by four, all digits
shift two places
to the left. to multiply by eight, all digits shift three places to the left. and so on.
What happens when you multiply a binary number by 2?
4 Answers. It is trivial from the bit operations perspective. Multiplying by 2 is equivalent to
a shift left by 1 bit
, division is a right shift. similarly it is the same trivial to multiply and divide by any power of 2.
What is successive multiplication?
In successive multiplication method,
Multiply the fractional part of the given decimal number by the desired base number to get a decimal number with integer part and fractional part
. Store the integer part of the product as Integer value and the factional part as the new fractional part.
When two N bit binary numbers are added the sum will contain at the most?
If two n-bit binary numbers are added then sum will contain
(n + 1) bit
at most. If summation results a carry then result will contain (n + 1) bit.
How do you multiply a negative number by a binary number?
When you multiply two negative numbers,in the last term you have to
write 2’s complement of the first number
.In this case 2’s complement of 1011 is 0101.
How does a processor add two numbers?
- Working right to left (least significant digit upwards) add together the two numbers.
- You may need to carry over a digit if the result exceeds a value you can display in a single digit. i.e. in base 10, 9 + 6 = 15. This is the same as 5, carry 1.
