Near the surface of the Earth (sea level), gravity decreases with height such that linear extrapolation would give zero gravity at a height of one half of the Earth’s radius – (9.8 m·s − 2 per 3,200 km.)
At what height above the surface of Earth is the value of g decreases by 2%?
Answer (2) Acceleration due to gravity above the surface of earth at a height h is given 2 ‘ 1 ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ e h g g R here, g ‘ = 0.98 g 2 0.98 1 e h R 2 0.02 e h R h = 0.01 R = 0.01 × 6400 km = 64 km 17 .
At what height above the surface of Earth is the value of g decreasing?
Near the surface of the Earth (sea level), gravity decreases with height such that linear extrapolation would give zero gravity at a height of one half of the Earth’s radius – (9.8 m·s − 2 per 3,200 km.)
At what height above the surface of Earth is the value of g decreasing by 36?
We can write the relation between actual acceleration due to gravity and the apparent acceleration due to gravity. Hence, the height above the surface of the earth where the acceleration due to gravity is reduced by 36% of its value on the surface of the earth is R4 . The correct option is (B).
At what height from the surface of earth will the value of g be reduced by 64?
⇒h=8000−6400= 1600 km . So at the height of 1600 Km the value of the g becomes 64%of the g. So this is the required answer. Hence option (A) is the correct answer.
