We can write the relation between actual acceleration due to gravity and the apparent acceleration due to gravity. Hence, the height above the surface of the earth where the acceleration due to gravity is reduced by 36% of its value on the surface of the earth is
R4
. The correct option is (B).
At what height from the surface of the earth will the value of g be reduced by 64?
⇒h=8000−6400=
1600 km
. So at the height of 1600 Km the value of the g becomes 64%of the g. So this is the required answer. Hence option (A) is the correct answer.
At what height from the surface of the earth will the value of G be reduced?
At what height from the surface of earth will the value of g be reduced by 36% from the value on the surface? Take radius of earth
R = 6400
km. Since the acceleration due to gravity reduces by 36% the value of acceleration due to gravity there is 100-36=64%.
At what height from the surface of earth will the value of g?
| Location Distance from Earth’s center (m) Value of g (m/s 2 ) | 50000 km above surface 5.64 x 10 7 m 0.13 |
|---|
At what height above the surface of earth the value of g is reduced to 1/4th of the value of g on earth’s surface?
Hence, the height above the surface of the earth where the acceleration due to gravity is reduced by [36% ] of its value on the surface of the earth is [dfrac{R}{4}] . The correct option is (B).
At what height h above the earth the value of g becomes g 2?
| Location Distance from Earth’s center (m) Value of g (m/s 2 ) | 1000 km above surface 7.38 x 10 6 m 7.33 |
|---|
What will be the acceleration due to gravity at height?
Hence, the acceleration due to the gravity of the body at height h is
7.35 ms
– 2
.
At what depth below the surface of Earth the value of g is same?
At what height from the surface of earth the acceleration due to gravity is the same as at a depth 160 km below the surface of Earth? Answer. Acceleration due to gravity will be same at height nearly equal
to 80 km
from earth’s surface.
Why does the earth impart the same acceleration to all bodies?
The force of gravitation exerted by the earth on a body of mass m isAcceleration imparted to the body g = Gm/R2
Clearly g does not depend on m. Hence the earth imparts same acceleration to all bodies.
How much below the surface of earth does the acceleration?
The value of acceleration due to gravity will be
1% of
its value at the surface of earth at a height of (Re=6400 km).
At what altitude the value of g becomes one fourth?
At
height R
the value of g becomes 1/4 to that on the earth.
At what height above the earth’s surface the acceleration due to gravity will be 1 9 th of its value at the earth’s surface radius of Earth is 6400 km?
the acceleration due to gravity will be 1/9th of its value at the earth’s surface.
Re = 6400km 21
. If the radii of the two planets be r1 and r2 and their mean densities d1 and d2.
At what altitude above the earth’s surface is the acceleration due to gravity equal to g 4?
6.37×106 m
.
What will happen to g if earth stops rotating?
Thus, as the earth stops rotating, the value of acceleration of gravity at any
point p will increase by an amount of Rω2cos2α everywhere except the poles
. So, the correct answer is “Option C”. Additional Information: … Hence, the acceleration due to gravity increases.
At what height above the surface of the earth is the value of g decreases by 2%?
Answer (2) Acceleration due to gravity above the surface of earth at a height h is given 2 ‘ 1 ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ e h g g R here, g ‘ = 0.98 g 2 0.98 1 e h R 2 0.02 e h R h = 0.01 R = 0.01 × 6400 km = 64 km 17.
Where is acceleration due to gravity is maximum?
g’ = g Thus acceleration due to gravity is least at the equator and maximum
at the poles
.
