8K∗16=213∗16, thus
13 address lines
and 16 data lines.
How many address bits are needed to operated a 8K 8 ROM?
How many address bits are needed to operated a 8k 8 ROM? Number of bits required to address 8 bits in 2048 x 8 chip is
3
.
How many bits should a 8K RAM hold?
8K∗16=213∗16, thus
13 address lines
and 16 data lines.
How many address bits are required for a 1024 8 memory?
Or 1024*8 gives 8192, or 2^13. so
13 bits
. If it ain’t a 1024 bits multiplied by 8 bits, or there are 1024 arrays of each size of 8 bit, then 1024 arrays, so 10 bits of addresses will do it.
How many bits is 8GB address?
8GB = 1GW (64 bit word = 8 bytes/word), which requires
30 bits
(log 2 1G = 30). The memory address is divided into line number and word number.
How many address bits are required to represent 4k memory?
So,
12 bits
are needed to address 4k memory locations.
Which term is not used to describe the memory component of a computer?
In computing, memory is a device or system that is used to store information for immediate use in a computer or related computer hardware and digital electronic devices. The term memory is often synonymous with the term
primary storage or main memory
. An archaic synonym for memory is store.
How many address bits are required for a 512 * 8 memory?
If only the number of words is increasing then all chips will be arranged vertically. In this case, only the number of words is increasing (128-512) so all chips will be arranged vertically. In a 512 x 8 RAM, there is a 9-bit address, we will divide this 9-bit address into 2 and
7-bit addresses
.
How many address bits are required for a?
Therefore 32 bits are required to uniquely address each 32-bit word. Therefore 34 bits are required to uniquely address each byte. . Therefore
28 address bits
are needed.
How many bits are required in the address for memory of 32 GB in size?
So you will need, at least
25 bits
to address a single byte in that memory scheme.
What is the amount of bits required to address 256mb?
This answer has been awarded bounties worth 50 reputation by Niklas R. You need log2(n) bits to address n bytes. For example, you can store 256 different values in an 8 bit number, so
8 bits
can address 256 bytes. 2
10
= 1024, so you need 10 bits to address every byte in a kilobyte.
How many numbers can be represented with 7 bits?
| Length of bit string (b) Number of possible values (N) | 7 128 | 8 256 | 9 512 | 10 1024 |
|---|
How many bits does it take to address a 1MB memory?
For example, you can store 256 different values in an 8 bit number, so 8 bits can address 256 bytes. 2
10
= 1024, so you need 10 bits to address every byte in a kilobyte. Likewise, you need
20 bits
to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte.
How many different addresses are required by the memory that contain 8K words?
Both simply have 8k of addressable words and therefore need
13 address lines
.
How many address lines does a 64kB memory device have?
3 Answers. One address addresses one byte. Using 16 bits, you can write
65536 addresses
(from 0 to 65535, that’s 65536 different addresses), and address 65536 bytes.
