Substituting it to the formula and simplifying gives us: There are
252 ways
to select 5 problems from 10 possible problems.
How many different sets of 5 cards each can be formed from a standard deck of 52 cards?
(52−5)! 5! =
2598960 different ways
to choose 5 cards from the available 52 cards.
How many different selections can be made if the students may only answer 8 out of 10 questions in an examination?
How many ways are there to choose the 2 questions that aren’t answered? Since the first 3 questions must be answered, there are (72)=21 choices for the 2 questions that aren’t answered, so there are
21 ways
to choose 8 of the 10 questions if your choice is required to include the first 3 questions.
How many ways can a student answer 6 out of 10 questions?
of different possible ways the student can choose 6 questions are. ⇒ (5 × 10) + (10 × 10) + (10 × 5) =
200 ways
.
How many combinations of 5 items are there?
Note that your choice of 5 objects can take any order whatsoever, because your choice each time can be any of the remaining objects. So we say that there are 5 factorial = 5! = 5x4x3x2x1 =
120 ways
to arrange five objects. In general we say that there are n!
How many ways are there to choose 3 objects out of a collection of 5?
So 5 choose 3 =
10 possible combinations
.
How many ways of possible sets of 5 cards you can get from a deck of cards if you do not care the order of the card?
You have 52 possible choices for the first card, 51 possible choices for the second card and so on. And you need 5 cards, it’d come down to this calculation: 52 x 51 x 50 x 49 x 48 =
311,875,200
. That’s the answer.
How many ways are there to select a 5 card poker hand from a standard deck of 52 cards such that at least one of the cards is a club?
So that’s 13C2 * 13C1 * 13C1 * 13C1 * 4 = 685,464 out of the 52C5 =
2,598,960 possible poker
hands.
How many possible 5 card hands are there?
Probability of a Full House
First, count the number of five-card hands that can be dealt from a standard deck of 52 cards. We did this in the previous section, and found that there are
2,598,960 distinct poker hands
. Next, count the number of ways that five cards can be dealt to produce a full house.
How many ways can you choose one or more students from 3 students?
in
7 ways
we can select the students……
How many ways can a student choose 4 out of six questions in an examination?
Out of 8 the first 2 have to be answered. That leaves him/her to choose 4 out of 6, that is 6C4 =
15 ways
.
How many ways can a committee of 5 members be chosen from 10 members?
5! Therefore, the number of ways of selecting a committee of 5 members from a group of 10 persons is
252
.
How many ways can a student select four questions from an exam containing 10 questions?
Here, there are 4 choices per question, and 10 questions. Choosing an answer for each question is a sequential task, so there are 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4=
410 ways
to answer.
How many choices should a student have if they attempt 6 out of 10?
R D Sharma – Mathematics 9
Number of ways to attempt more than 4 from each group. Hence, our required ways =
200
.
How many ways can a committee of 6 be selected from a club of 10 members?
= 20 * 6 =
120 Ways
.
How do you find combinations with 5 numbers?
Assuming no five-digit number can begin with zero, there are 9 possible choices for the first digit. Then there are 10 possible choices for each of the remaining four digits. Therefore, you have 9 x 10 x 10 x 10 x 10 combinations, or 9 x 10^4, which is
90,000 different combinations
.
How many ways can 5 different keys be arranged on a keyring?
This happens in a circular pattern, while in a linear pattern the 5 keys can be arranged in 5! ,=
120 ways
.
How many ordered 5 card cards can be drawn from a deck of 52 cards without replacement?
Correct answer:
The key points we need to remember are that order matters and that we are sampling without replacement. This then becomes a simple permutation problem. We have 52 cards to be chosen 5 at a time, so the answer is
52 * 51 * 50 * 49 * 48
.
How many ways can a 5 digit number be arranged?
The smallest is 21345, the largest is 25431 and again there are 24 possibilities. Repeat this process again with 3 as the first digit, then 4 as the first digit and finally 5 as the first digit. In total you will find 5 × 24 =
120 possibilities
.
How many ways can you pick 3 out of 8?
Lauren calculated-correctly- that it’s possible to choose 3 people from 8 in
56 ways
.
How many ways can a 5 card hand contain two pair?
If we order the 5-card hand with the two pairs first, we have 13C2 choices for the two numbers showing on the two pairs. Each pair will have two out of four suits. Thus, we have 4C2·4C2 = 6·6 =
36 ways
to choose the suits.
How many 5 cards are in a deck?
Originally Answered: How many 5s are in a deck of cards? A deck of cards consists of 13 cards in each of four suits for a total of 52. As there are four suits and every suit includes one 5, there are
four 5s
.
How many ways are there to draw a hand of cards that have at least two different suits?
A hand with two suits has either four cards from one suit and one from the other, or three cards from one suit and two from the other. There are
12 ways
to choose the major and minor suits. For each (ordered) pair of suits, there are (134)(131)+(133)(132)=31603 ways to make a hand; the result is 12×31603=379236 again.
What is the probability that a 5 card poker hand contains at least one ace?
This probability is
(485)(525)
, for we have 48 choose 5 possible hands with no aces. Then the solution to the problem – that is, the probability of at least one ace appearing in a 5-card hand – is one minus the complement: 1−(485)(525).
How many 5 card hands have at least two cards with the same rank?
So there are
(135)⋅4
5 ways of choosing 5 cards, all of different ranks. Now as you said, (525) is the total number of hands with 5 cards. So subtracting (135)⋅45 from (525) gives number of hands of 5 cards where at least two cards are of the same rank.
How many ways are there to distribute hands of 5 cards to each of four players?
How many ways can you make five packs of four cards each? The first pack can be made 52C4 =
270,725 ways
.
What is the value of 18c3?
(n – r)! = (18 – 3)! (18 – 3)! =
15
!
How many ways can you choose 3 questions to answer in a 5 item test?
So there are
10 ways
of choosing the 3 questions.
How many ways can a student answer 6 out of 10 questions?
of different possible ways the student can choose 6 questions are. ⇒ (5 × 10) + (10 × 10) + (10 × 5) =
200 ways
.
How many different ways are there to have a four of a kind in five card poker?
| hand number Probability | 4-of-a-kind 624 .00024 | full house 3,744 .00144 | flush 5,108 .0020 | straight 10,200 .0039 |
|---|
How many combinations of 3 students can we make from a class of 15 students?
Therefore, the answer to this question is: Now, if the order of the groups DID matter, we would need to multiply by how many ways those 3 groups can be arranged, or 3!. That means if the order of the groups is important, the number of ways would be
216216
.
How many ways can a student choose 8 questions out of 10 in an exam?
Thus, the number of ways by which a student can choose 8 out of 10 questions to answer on an exam is
45
.
How many ways can you select a committee of 5 students?
There are
252 ways
to select a committee of five members from a group of 10 people.
How many ways can a committee of 5 members be selected from 5 seniors and 4 juniors?
36 x 35 =
1260 ways
to pick the committee. If the objects are distinguishable (say, 1, 2, 3, 4 and 5) and the groups are distinguishable (say A, B and C) then there are 3^5 = 243 ways.
How many ways can a team of 5 persons?
As either of the two can be selected as the first member this makes a total of 2*70 =
140 ways
. In how many ways can a team of 5 persons be formed out of a total of 10 persons such that two particular persons should not be included in any team?
