How much time in seconds does the ball spend in the air before it reaches the ground? 1 Expert Answer The ball hits the ground after
4 seconds
.
How much time does the ball spend in the air before it reaches the ground?
It takes
about 88 seconds
for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or 2 minutes and 56 seconds, until the cannonball destroys the cannon that fired it.
How much time does the ball spent in the air?
It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or
2 minutes and 56 seconds
, until the cannonball destroys the cannon that fired it.
How do you calculate the time a ball is in the air?
The time in the air will be the same as if the ball was hit straight up and then came straight down so we won’t even need to worry about the 180 meters. Another of the kinematic equations
At what velocity does the ball hit the ground?
Conclusion: The magnitude of the velocity of the ball is
26.3 m/s
for the parabolic motion just before it hits the ground and this greater than the 17.1 m/s for the velocity of the ball that falls straight downward.
At what speed do you have to throw a ball upwards into the air in order for the ball to reach a maximum height of 15 meters and how long will the ball be in the air?
Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer:
0 m/s
. The instantaneous speed of any projectile at its maximum height is zero.
How long does it take the ball to reach its maximum height?
It takes
about 88 seconds
for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or 2 minutes and 56 seconds, until the cannonball destroys the cannon that fired it.
How long does it take something to hit the ground?
Measure the distance the object will fall in feet with a ruler or measuring tape.
Divide
the falling distance by 16. For example, if the object will fall 128 feet, divide 128 by 16 to get 8. Calculate the square root of the Step 2 result to find the time it takes the object to fall in seconds.
What is the maximum height?
The maximum height of the object is
the highest vertical position along its trajectory
.
How long is a 4 second fall?
Falling for 4 seconds would give you a
velocity of roughly 87mph
, enough to kill the vast majority of people. This speed is the terminal velocity. According to Newton’s first law, at that point, the falling body stops accelerating and moves at a constant speed.
How do you find velocity with time and height?
Take the square root of the result
to calculate the time it takes for the object to drop. For example, the square root of 1.02 s^2 equals 1.01 s. Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground.
What is the acceleration of the ball after 1 second?
After 1 second, the velocity is 4.5+1.5=
6 m/s
.
What units are for velocity?
| Derived quantity Name Symbol | speed, velocity meter per second m/s | acceleration meter per second squared m/s 2 | wave number reciprocal meter m – 1 | mass density kilogram per cubic meter kg/m 3 |
|---|
How fast must a ball be thrown upward to reach a height of 12m?
The velocity with which a ball must be thrown vertically upwards so that it reaches a height of 12 m is
approximately 15.33 m/s
.
What happens when you throw a ball upwards?
Vertical motion under gravity. When you throw an object upwards,
it will eventually fall back to the ground under the earth’s gravity
. … An object that is thrown vertically upwards decelerates under the earth’s gravity. Its speed decreases until it attains a maximum height, where the velocity is zero.
When the golf ball reaches the maximum height does it momentarily stop or not?
Velocity in the Y direction at the halfway point, or
midpoint (V
y
, mid) is zero
. This is because when the ball reaches its highest point, it stops momentarily before reaching the ground.
