Yes,
the merry-go-round is accelerating
. Even if the merry-go-round is going around in a circle at constant angular speed, the linear speed constantly…
What is the angular acceleration of the merry go round?
The angular accelerations found are quite large, partly due to the fact that friction was considered to be negligible. If, for example, the father kept pushing perpendicularly for 2.00 s, he would give the merry-go-round an angular velocity of 13.3 rad/s when it is empty but only
8.89 rad/s when
the child is on it.
How merry go round moves?
Physics tells us that objects at rest want to stay at rest, and those in motion want to stay in motion, and when these objects are in motion, they naturally move in a straight line. … A force is required for an object to move in a circle, as is the case with a merry-go-round. This force is called a
centripetal force
.
Is a merry go round constant velocity?
To have constant velocity, an object has to have both a constant speed and a constant direction. Since the merry go round is a circle, even if its speed is constant, its direction is always changing.
A merry go round does not have a constant velocity
.
Is going around in circles accelerating?
The velocity vector is constant in magnitude but changing in direction. … For this reason, it can be safely concluded that an object moving in a
circle at constant speed is indeed accelerating
. It is accelerating because the direction of the velocity vector is changing.
What is positive acceleration?
An object which moves in the positive direction has a positive velocity. If the object is speeding up, then
its acceleration vector is directed in the same direction as its motion
(in this case, a positive acceleration).
Can a body have constant speed and still be accelerating?
Since speed is equal to the magnitude of the velocity vector, it will also be constant. Again, since the acceleration is the rate of change of velocity of a body with time, if the velocity is constant, the acceleration of the body will be
zero
. … Hence, a body can have a constant speed and still be accelerating.
What is tangential acceleration formula?
The tangential acceleration
= radius of the rotation * its angular acceleration
. It is always measured in radian per second square. Its dimensional formula is [T
– 2
]. … When an object makes a circular motion, it experiences both tangential and centripetal acceleration.
How long does it take the father to give the merry-go-round an angular velocity of 1.50 rad s?
So this is 1.50 radians per second— final angular velocity—minus 0 times this moment of inertia divided by 250 newtons—the force applied by the father— times 1.50 meters— the distance from the center to where the force is applied— these are perpendicular and we get
0.338 seconds
.
How long does a merry-go-round last?
An average ride length is
2 to 3 minutes
. The speed of the ride is low in order to keep centrifugal force low because the faster it turns the more centrifugal force the ride will have.
Is a child on a merry go round accelerating?
On a merry-go-round, you are moving at a constant speed but you are continually changing direction. Hence
you are accelerating
because the velocity is continually changing.
What force throws you off a merry go round?
As on the merry-go-round, any motion in Earth’s northern hemisphere experiences
a Coriolis force
to the right.
Which motion is merry go round?
The merry-go-round is
spinning
. Therefore, it is a rotational motion problem.
Who goes faster on a merry go round?
All of the
horses
move through one complete revolution in the same amount of time. The horses on the outside of the carousel have to cover more distance than the inside horses in this of time. This means the horses on the outside have a faster linear speed than those at the hub.
Is a merry go round faster on the outside?
No, you are going faster
. The merry-go-round is rotating with uniform circular motion – that means that it rotates at a constant angular speed. … Since you are circling with uniform circular motion w is the same for both of you meaning that the closer you are to the centre the slower your linear speed is.
Is centripetal force equal to normal force?
Only the normal force has
a horizontal component, and so this must equal the centripetal force—that is, Nsinθ=mv2r θ = m v 2 r .
