Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108 . Thus, 3x+6=108.
What are three consecutive integers that have a sum of 84?
The sum of three consecutive even number is 84. Let the number be 2*n , 2*n + 2 and 2*n + 4. The required numbers are 26 , 28 and 30 . Let the first even integer be x, Then the next even integer is (x+2) and the third is (n+4).
What are the 3 consecutive integers with a sum of 63?
Therefore, three consecutive integers that add up to 63 are 20, 21, and 22 .
What are three consecutive integers that have a sum of 54?
Explanation: Let x= our first even integer. Therefore our three consecutive even integers are 16 , 18 , and 20 .
What are 3 consecutive integers that have a sum of 99?
Either way you will find the three consecutive integers whose sum is 99 are 32, 33, and 34 .
What three numbers equal 99?
The factors of 99 are 1, 3, 9, 11, 33, and 99 .
What is the sum of the first 99 consecutive positive integers?
Therefore, 4950 is the sum of positive integers upto 99.
What three consecutive integers have a sum of 72?
- Let the three consecutive numbers be x,x+1,x+2 .
- x+x+1+x+2=72.
- 3x+3=72.
- 3x=69.
- x=23.
- 23,24,and25 and the smallest one is 23 .
What 3 consecutive integers have a sum of 51?
Hence, we have obtained three consecutive numbers as 16, 17 and 18 . So, the correct answer is “Option (d)”. Note: Another method to solve this is by assuming the variables p – 2, p – 1 and p. Then also, the sum would be 51 and we would get the value of the number as 16, 17 and 18.
What is the integer of 63?
| ← 62 63 64 → | ← 60 61 62 63 64 65 66 67 68 69 → List of numbers — Integers ← 0 10 20 30 40 50 60 70 80 90 → | Cardinal sixty-three | Ordinal 63rd (sixty-third) | Factorization 3 2 × 7 |
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What two consecutive numbers have a sum of 54?
two consecutive even numers are 26 & 28 , whose sum is 54.
What two consecutive even integers have a sum of 38?
➦ The two consecutive even numbers whose sum is 38 are 18 and 20 .
What three consecutive odd integers have a sum of 57?
And also an odd number just after n will be (n+2). Therefore, the required three consecutive odd numbers are 17, 19 and 21 . Hence, option (a) is the correct answer.
