In 8085 Instruction set, MOV is a mnemonic, which
stands for “MOVe”
. In this instruction 8-bit data value in register r2 will be moved to the 8-bit register r1. … This instruction uses register addressing for specifying the data.
Which type of instruction is mov?
Mnemonics, Operand Opcode Bytes | MOV H, M 66 1 | MOV L, M 6E 1 |
---|
What is the MOV instruction?
The MOV instruction
moves data bytes between the two specified operands
. The byte specified by the second operand is copied to the location specified by the first operand. The source data byte is not affected.
What is the purpose of MOV instruction?
The mov instruction
copies the data item referred to by its second operand
(i.e. register contents, memory contents, or a constant value) into the location referred to by its first operand (i.e. a register or memory).
What is MVI and MOV in microprocessor?
MVI instruction copies data between two registers
, whereas MOV instruction transfers an immediate data into a register. MOV instruction copies data between two registers, whereas MVI instruction. Microprocessors and Microcontrollers – – Unit 3…
What is wrong with the MOV bl CX instruction?
6. The
MOV bl
,
cx instruction
is
wrong
because the contents of
cx
are to big for
bl
. 7. The
MOV
ds,ss
instruction
is
wrong
because segment to segment transfer is not allowed.
What does instruction MOV A r1 mean?
In 8085 Instruction set, MOV is a mnemonic, which stands for “
MOVe
”. In this instruction 8-bit data value in register r2 will be moved to the 8-bit register r1. … It is a 1-Byte instruction.
Which flag is affected by MOV instruction?
The
MOV instruction never affects the flags
. Whenever the destination operand equals Zero, the Zero flag is set. A flag is set when it equals 1. A flag is clear when it equals 0.
What is the action of MOV B A in microprocessor?
MOV A, B:
Move the content of B register to register A.
78: The instruction in the code form. In the above example, MOV A, B is 78H. Besides the operation to be performed the opcode also specifies source and destination registers.
What does mov ah 4CH mean?
MOV AH, 4CH means
store (or “move”)
the hexadecimal value 4C into register AH . … In MS-DOS, invoking interrupt 21h while AH = 4Ch causes the current process to terminate and uses the value of register AL as the exit code of the process.
What is the function of MOV A 21h?
Function number Description | 01h e.g. mov ah,01h int 21h Keyboard input with echo: This operation accepts a character from the keyboard buffer. If none is present, waits for keyboard entry. It returns the character in AL. |
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What is the addressing mode used in instruction MOV MC?
Indirect addressing mode
In this mode, the data is transferred from one register to another by using the address pointed by the register. For example, MOV A, M: means data is transferred from the memory address pointed by the register pair HL to the register A.
Why addressing modes are used?
Addressing modes are an aspect of the instruction set architecture in most central processing unit (CPU) designs. … An addressing mode
specifies how to calculate the effective memory address of an operand by using information held in registers and/or constants contained within a
machine instruction or elsewhere.
What is the function of LDA 2000h instruction?
In 8085 Instruction set, LDA is a mnemonic that stands for LoaD Accumulator with the contents from memory. In this instructionAccumulatorwill get initialized with 8-bit content from the 16-bit memory address as indicated in the instruction as a16. This instruction uses
absolute addressing for specifying the data
.
What is the meaning of MOV a B?
assembly microprocessors 8085. In assembly language, instruction MOV A B. means
moving the content of B (source) to A (destination)
.
What is the purpose of Xchg instruction?
In 8085 Instruction set, there is one mnemonic XCHG, which stands for eXCHanGe. This is
an instruction to exchange contents of HL register pair with DE register pair
. This instruction uses implied addressing mode. As it is1-Byte instruction, so It occupies only 1-Byte in the memory.