Answer. the maximum resistance which can be made using 5 resistors each of 1/5 ohms is 1 ohm .
Thus the value of maximum resistance is 2 ohm .
The maximum resistance of five resistors is 1 ohm .
So, maximum resistance can be obtained only when those 10 given resistors are arranged in series combination. So , max resistance obtained by connecting the ten resistances are 10 ohm .
What is the minimum resistance which can be made using five resistors each of (1//5) Omega ? Minimum resistance is obtained in parallel combination. Thus, Rp=(1/5Ω)5=(1/25)Ω .
It is know to us , combining resistances in parallel reduces equivalent resistance and combining resistances in series increases equivalent resistance. To get maximum possible resistance, one has to combine all 5 resistors in series. Rmax=R1+R2+R3+R4+R5 Rmax=R+R+R+R+R=5R. Rmax=5×51= 1Ω
While equivalent resistance increases when resistors are joined in series e.g., Req = R1 + R2 + R3 + .... + Rn. it Means, we can get minimum resistance when all the given resistors will join in parallel. And we can get maximum resistance when all the resistors will join in series .
the maximum resistance which can be made using 5 resistors each of 1/5 ohms is 1 ohm .
The minimum resistance which can be made using five resistors is 0.04 ohms . Explanation: In parallel combination of resistors, the equivalent resistance is minimum.
Answer: 5 ohm is the minimum resistance we get.
Take the nominal value and multiply it by 1 + your tolerance , which is (1+0.1). Then take the nominal value and multiply it by 1 – tolerance, or (1-0.1).
therefore the effective resistance between A and B is 10Ω
What is the maximum resistance which can be made using five resistors each of (1//5) Omega ? Maximum resistance is obtained in series combination. Thus, Rs=5(15Ω)=1Ω .
Step-by-step explanation:
5 ohm is the minimum resistance we get.
Hence, the minimum resistance which can be made using five resistors each of 1/5 ohms is 1/25 ohms.
Explanation: I=V/R. Since in parallel circuit, voltage is same across all resistors. Hence across the 20 ohm resistor, V=200V so I=200/20=10A. ... Current through 20 ohm equals 200 divided by 20 equals to 10 amp .
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