The speed of the bullet just before it hit the block was
about 150 m/s
.
What is the net momentum of the bullet block system before the collision?
Express your answer in terms of and other given quantities. The momentum of the block/bullet system is conserved. Therefore, the momentum before the collision is
the same as the momentum after the collision
.
What is the speed of the bullet block center of mass?
Prior to the collision, the center of mass of the two-block system has a speed of
3.00 m/s
.
Was the collision between the wood block and the bullet elastic or inelastic?
If the block rotates, then additional kinetic energy is transferred from the bullet to the block. The bullet and block problem represents a
completely inelastic collision
where the bullet remains embedded in the block after the collision.
Is momentum conserved while the bullet block combo is swinging?
The impact of the bullet with the block conserves momentum
, but a great deal of kinetic energy is lost to things like heat and work ripping through wood fibers. The moving post-collision bullet and block combo swing on the string to some height, and in this, kinetic energy turns to potential.
What happens when two balls of equal mass collide?
Two balls with equal masses, m, and equal speed, v, engage
in a head on elastic collision
. … Since the balls of equal mass are moving at equal and opposite speeds, the total linear momentum of the system is zero. For linear momentum to be conserved after the collision, both balls must rebound with the same velocity.
How do you find the speed of an object before a collision?
In a collision, the velocity change is always computed by
subtracting the initial velocity value from the final velocity value
. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
Is momentum conserved with gravity?
Momentum is conserved in case of motion under gravity
because a object is pulled by the earth and the earth of pulled by the object. … Gravity is an internal force, so it cannot change the net mechanical energy but it can transform KE into PE and PE into KE.
What happens to the momentum of a bowling ball after hitting a bowling pin?
When one moving object collides with another moving object, the motion of both objects changes. For example, when a bowling ball strikes the pins, the bowling ball slows down.
It loses momentum
. … The important thing to remember is that the TOTAL momentum of the ball and the pins remains the same.
Which situation will produce the greatest change of momentum?
The greatest change in momentum will only be produced by
a larger force acting over a short time
.
Do objects stick together in an inelastic collision?
People sometimes think that objects must stick together in an inelastic collision. However,
objects only stick together during a perfectly inelastic collision
. Objects may also bounce off each other or explode apart, and the collision is still considered inelastic as long as kinetic energy is not conserved.
Is angular momentum conserved?
Angular momentum, like energy and linear momentum,
is conserved
. This universally applicable law is another sign of underlying unity in physical laws. Angular momentum is conserved when net external torque is zero, just as linear momentum is conserved when the net external force is zero.
When two bodies stick together the collision is said to be?
If two bodies stick together after collision and move as a single body, the collision is said to be
inelastic
.
Is momentum conserved in a pendulum?
While not all of the energy from the bullet is transformed into kinetic energy for the pendulum (some is used as heat and deformation energy) ,
the momentum of the system is conserved
. … In the case of a pendulum total mechanical energy is conserved.
Can an impulse be negative?
Impulse is a vector, so a negative impulse
means the net force is in the negative direction
. Likewise, a positive impulse means the net force is in the positive direction.
What type of energy does the bullet block have immediately after the bullet embeds post collision )?
Let’s figure out the ratio of the mechanical energy after the collision to the mechanical energy before the collision. This is equal to the ratio of the
kinetic energy
of the block + bullet immediately after the collision to the kinetic energy of the bullet before the collision.
