The golf ball is on the ground when it is hit, and it is on the ground again 15 seconds later. The golf ball reaches a maximum height of 13.5 meters after 1.25 seconds. After 2.5 seconds, the golf ball is at the same height above ground as when it was first hit. The golf ball reaches a maximum height of
45 meters
.
What is the height of the ball after 2.5 seconds?
The golf ball is on the ground when it is hit, and it is on the ground again 15 seconds later. The golf ball reaches a maximum height of 13.5 meters after 1.25 seconds. After 2.5 seconds, the golf ball is at the same height above ground as when it was first hit. The golf ball reaches a maximum height of
45 meters
.
How high is the ball after second?
After 1 second, the height of the ball is
86 feet
.
What is the height from which the ball is thrown?
Projectile Motion. An object is thrown straight up from the top of a building h feet tall with an initial velocity of v feet per second. The height of the object as a function of time can be modeled by
the function h(t) = –16t
2
+ vt + h
, where h(t) is the height of the object (in feet) t seconds after it is thrown.
How can I get my height after t seconds?
After t seconds, the height of the ball is given by the equation
h=-16t^2+55t+6
.
What is formula of height?
How to Calculate Height By Geometry. … So, “
H/S = h/s
.” For example, if s=1 meter, h=0.5 meter and S=20 meters, then H=10 meters, the height of the object.
What is the maximum height the ball can reach?
The maximum height reached by a ball is
0.45 meters
.
How high is the ball after 3 seconds?
After 3 seconds, the height of the ball is
150 feet
.
What is the acceleration of the ball after 1 s?
After 1 second, the velocity is 4.5+1.5=
6 m/s
.
How many seconds until the max height is reached?
1 Expert Answer
So the ball reaches its maximum height after
3 seconds
.
How do you find the maximum height in free fall?
y = v 0 2 − 2 g = ( 2.0 × 10 2 m / s ) 2 − 2 ( 9.8 m / s 2 ) =
2040.8 m
. This solution gives the maximum height of the booster in our coordinate system, which has its origin at the point of release, so the maximum height of the booster is roughly 7.0 km.
How do you find maximum height reached?
- if α = 90°, then the formula simplifies to: hmax = h + V02 / (2 * g) and the time of flight is the longest. …
- if α = 45°, then the equation may be written as: …
- if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.
How far does the ball drop in the next 8 seconds?
The distance travelled in the next 8 seconds is then s(4+8)-s(4)=-5*144-(-80)=-720+80=-640 so it drops an additional
640 meters
.
Is height a function of time?
A yo-yo moves straight up and down. Its height above the ground, as a function of time, is given by the
function
, where t is in seconds and H(t) is in inches.
How do you find initial height?
Solution: Choose the formula
h = -16t
2
+ v
0
t + h
0
. The initial velocity, v
0
= 200 ft/sec and the initial height is h
0
= 0 (since it is launched from the ground). Formula: h = -16t
2
+ 200t + 0.
