How far away does the cannonball land? A cannon is fired towards the edge of a cliff. It is found that if the cannon is fired at exactly 38 degrees above horizontal then the cannonball will just barely touch the edge of the cliff, which is 313 meters away .
How far will the ball travel before it hits the ground?
The ball will travel about 1.1 meters before hitting the ground. Projectile motion problems always have this kind of two-step structure (at least).
How far away will the projectile land?
The projectile will land ≈397 meters from its launch point.
How far from the base of the cliff will the ball land?
The red ball will land 70 meters from the base of the cliff.
How do you calculate how far a ball is thrown?
- Horizontal distance can be expressed as x = V * t .
- Vertical distance from the ground is described by the formula y = – g * t2 / 2 , where g is the gravity acceleration and h is an elevation.
How far will the cannonball travel horizontally?
The range of the cannon is 770 m . The shot is horizontal, so there is no initial vertical velocity.
What is the maximum range of projectile?
The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees .
How high will a ball go if it is thrown upward with a speed of 15 m s?
A ball is thrown up with a speed of 15 m/s . How high wiil it go before it begins to fall ? (g=9.8 m//s^(2) Please note that here the ball is going up against the gravity ,so the value of g is to be taken as negative . Thus the ball will go the a maximum height of 11.4 meters before of begins to fall.
What determines the highest elevation attained of a projectile?
The peak height of a projectile is determined by the initial value of the vertical velocity component . The greater the initial value of v y , the higher that a projectile will rise. The projectile launched at 60-degrees has the greatest v y , and as such the greatest peak height.
How do you find when a projectile will hit the ground?
- Horizontal velocity component: Vx = V * cos(α)
- Vertical velocity component: Vy = V * sin(α)
- Time of flight: t = 2 * Vy / g.
- Range of the projectile: R = 2 * Vx * Vy / g.
- Maximum height: hmax = Vy2 / (2 * g)
What affects the slowing down and eventually stopped the ball from rolling?
The force in question is friction . ... There is also friction between the ground and part of the ball that touches the ground as it rolls. The friction force acts in the opposite direction to the motion of the ball, slowing it and eventually stopping it.
What affected the distance Travelled by the ball?
The greater the air pressure in the ball , the farther it will travel when a force is applied. ... The student will learn about the relationship between air pressure and friction: the lower the friction, the farther the ball will go.
Why is 45 degrees the optimal angle for projectiles?
The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.
How many mph does a cannonball go?
The Cannonball Run: A journey and a race, run at warp speed. Or about 80 mph . Police officers often know cars well, Tabbutt said, but the countermeasures are designed to confuse even if just for a moment, which could make the difference if they are pulled over.
How fast does a cannonball go mph?
106 mph (171 km/h) average.
Which projectile has the longest time of flight?
Since ball A has the highest trajectory, it will have the longest flight time. Simulation Note: Ball A was launched at 50°, Ball B at 40° and Ball C at 30°.
